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2004-10-31, 10:19 AM | [Ignore Me] #1 | ||
Lightbulb Collector
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You have 12 coins. These are the most valuable coins, ever. Don't ask what's in them. However, one of them is impure by just a tiny bit. However, you do have The World's Best Scale to help you. TWBS can sense impurity to a bajillionth of a gram and will exxagurate the difference between two objects of different mass so that one that is even slightly off in weight will be shown by a big change.
However, the guy who owns it is a total prick, and you only have enough money to use it THREE times. Furthermore, you don't know if the impurity is a lighter or heavier substance- meaning that if one coin is heavier than the other, you know nothing. Come up with a straightforward strategy to find the coin. ONE guy solved this in our Physics class.
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The gun katas. Through analysis of thousands of recorded gunfights, the Cleric has determined that the geometric distribution of antagonists in any gun battle is a statistically predictable element. The gun kata treats the gun as a total weapon, each fluid position representing a maximum kill zone, inflicting maximum damage on the maximum number of opponents while keeping the defender clear of the statistically traditional trajectories of return fire. By the rote mastery of this art, your firing efficiency will rise by no less than 120%. The difference of a 63% increase to lethal proficiency makes the master of the gun katas an adversary not to be taken lightly. |
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2004-10-31, 10:25 AM | [Ignore Me] #3 | ||
Lightbulb Collector
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It's not homework. By the way, I found an alternate way to solve this.
Because nobody on Earth will get this, I will allow you to post the answer in the thread.
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The gun katas. Through analysis of thousands of recorded gunfights, the Cleric has determined that the geometric distribution of antagonists in any gun battle is a statistically predictable element. The gun kata treats the gun as a total weapon, each fluid position representing a maximum kill zone, inflicting maximum damage on the maximum number of opponents while keeping the defender clear of the statistically traditional trajectories of return fire. By the rote mastery of this art, your firing efficiency will rise by no less than 120%. The difference of a 63% increase to lethal proficiency makes the master of the gun katas an adversary not to be taken lightly. |
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2004-10-31, 10:43 AM | [Ignore Me] #4 | ||
Major
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You have the worlds most valuable coins evar and you only have enough money to use the scales 3 times? sheesh.
I can only think of an answer for it you knew if it was heavier or lighter. I bet it's similar to this...
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Last edited by MrPaul; 2004-10-31 at 11:05 AM. |
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2004-10-31, 11:59 AM | [Ignore Me] #6 | ||
Lieutenant Colonel
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Very very simple.
12 coins, 3 scale uses. Look at the thing that shows a graph. If it's a straight line, weight going up by a steady amount with each coin being added... Ah hell, shoot the owner, take the coins, torch the scales. Nobody else will be able to tell which is fake.
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4 days left 'til 4 more years. |
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2004-10-31, 03:22 PM | [Ignore Me] #7 | ||
Brigadier General
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I put all the twelve coins, 6 on each side, on the scale one at a time, as soon as there is a difference, I stop, then begin to remove two from each side until the difference is gone, on the two coins I took away when it was gone, I weigh them both opposite each other, then one final time, I weigh the heavier coin, against a different coin, knowing it is authentic. Whether the scale stays the same when I replace the last coin, or whether is changes, affects which coin I will determine to be fake. Obviously, if in the final use of the weighing both coins were the same, then the coin I removed is obviously fake. If not, then it is the coin I didnt remove.
Technically speaking, placing the coins down two by two, is using it only once.
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2004-10-31, 03:33 PM | [Ignore Me] #8 | ||
you can only use it thre times Defud
put 6 coins on each side, take note of the differences take 3 coins of each side. if the sides are the same you know, besause of the difference recorded above and the mass of these times 2, witch group of three(not on the scale) is the one with the impure coin. if the sides are not the same you know for the same reasons above, what group of 3(on the scale) is the one with the impure coin. then put a coin on each side of the scale, if they are the same the on not on the scale is the impure one, if one is different based on results before you can figure out witch is witch.
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All opinions are not equal. Some are a very great deal more robust, sophisticated and well supported in logic and argument than others. |
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2004-10-31, 03:58 PM | [Ignore Me] #10 | ||
Lieutenant Colonel
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Answer
For now, let's say that we only have 9 coins. We can find the fake coin in three weighings, the first two as follows: Coins 1 2 3 against Coins 4 5 6 Coins 1 2 3 against Coins 7 8 9 That'll let us know which group has the fake coin. For example, if groups 1 2 3 and 4 5 6 balance out, but if group 1 2 3 falls while group 7 8 9 rises, we know the fake coin is in 7 8 9. Now, we do the third weighing to find the fake coin by putting a coin from each group on either side. Coins 1 4 7 against Coins 2 5 8 For 12 coins, we simply add three more coins to our groupings: 1 2 3 10 against 4 5 6 11 1 2 3 11 against 7 8 9 10 1 4 7 10 against 2 5 8 12 That should let you discover the fake coin.
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